Why does the arrow (- gt;) operator in C exist? - Stack Overflow Why does -> even exist? In one of the very first versions of C language (which I will refer as CRM for "C Reference Manual", which came with 6th Edition Unix in May 1975), operator -> had very exclusive meaning, not synonymous with * and combination The C language described by CRM was very different from the modern C in many respects
pointers - Arrow operator (- gt;) usage in C - Stack Overflow 348 I am reading a book called "Teach Yourself C in 21 Days" (I have already learned Java and C# so I am moving at a much faster pace) I was reading the chapter on pointers and the -> (arrow) operator came up without explanation
Difference between and in C? - Stack Overflow In early C, the operator did not exist, and because of that was used for this purpose One way to explain it is that you could imagine that is the same thing as applying on each individual bit in the operands Also note that has lower precedence than , even though intuition says that it should be the other way around
What is the -- gt; operator in C C++? - Stack Overflow After reading Hidden Features and Dark Corners of C++ STL on comp lang c++ moderated, I was completely surprised that the following snippet compiled and worked in both Visual Studio 2008 and G++ 4
How to understand the pointer star * in C? - Stack Overflow Declarations in C are expression-centric, meaning that the form of the declaration should match the form of the expression in executable code For example, suppose we have a pointer to an integer named p
math - How to use nan and inf in C? - Stack Overflow In C99, the C header <math h> defines nan(), nanf(), and nanl() that return different representations of NaN (as a double, float, and int respectively), and infinity (if avaliable) could be returned by generating one with log(0) or something There's no standard way to check for them, even in C99 The <float h> header (<limits h> is for integral types) is unfortunately silent about inf and nan
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